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Reasoning MCQ for IBPS PO/RRB

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Reasoning MCQ for IBPS PO/RRB 

Directions (Q. 1-5): Study the following information carefully to answer the given questions.
A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of the input and its rearrangement.
  • Input: 25 11 ice cage 12 it redact tacit 32 55
  • Step I: it 55 25 11 ice cage 12 redact tacit 32
  • Step II: ice 11 it 55 25 cage 12 redact tacit 32
  • Step III: cage 12 ice 11 it 55 25 redact tacit 32
  • Step IV: tacit 32 cage 12 ice 11 it 55 25 redact
  • Step V: redact 25 tacit 32 cage 12 ice 11 it 55
  • Step V : is the last step of the above input. 

As per the rules in the above steps, find out in each of the following  questions the steps for the input given below: 
Input: forsake 36 ebullience page 89 10 quack 42 amicable 56 21 redact

1. Which of the following steps would be the last step but one?
1) III
2) V
3) VI
4) IV
5) None of these

2. If in Step IV ‘42’ is related to ‘page’ and ‘redact’ is related to ‘10’ in a certain way. Following the same way, ‘quack’ is related to which of the following?
1) 89
2) amicable
3) 36
4) ebullience
5) None of these

3. What is the position of ‘forsake’ in Step III?
1) Sixth from the left
2) Eighth from the right
3) Sixth from the right
4) Fifth from the left
5) None of these

4. Which of the following will be Step V?
1) ebullience 36 amicable 89 forsake 42 redact 21 quack 56 page 10
2) amicable 89 forsake 42 redact 21 page 10 36 quack 56 ebullience
3) amicable 89 forsake 42 redact 21 quack 56 page 10 36 ebullience
4) Can’t be determined
5) None of these

5. How many steps will be required to complete the rearrangement?
1) Four
2) Five
3) Seven
4) Six
5) None of these

Directions (Q. 6-10): In each question below are given three statements followed by two conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts and then decide which of the given conclusions logically follows from the given statements, disregarding commonly known facts. Give answer
  1. if only conclusion I follows.
  2. if only conclusion II follows.
  3. if either conclusion I or II follows.
  4. if neither conclusion I nor II follows.
  5. if both conclusions I and II follow.
6. Statements: 
Some schools are colleges.

Some colleges are hostels.
No hostel is an institute.
Conclusions:
I. All institutes being colleges is a possibility.
II. No institute is a hostel.

7. Statements: 
All nails are hammers.
All hammers are needles.
Some needles are threads.
Conclusions:
I. At least some threads are hammers.
II. All hammers being nails is a possibility.

8. Statements: 
Some stones are shells.
All shells are boxes.
All boxes are pearls.
Conclusions:
I. Some shells are pearls.
II. Some stones are boxes.

(9-10):
Statements: 
All chains are bangles.
Some bangles are pendants.
No pendant is a ring.

9. Conclusions:
I. Some chains are pendants.
II. No chain is a bangle.

10. Conclusions:
I. Some rings being pendants is a possibility.
II. Some bangles are chains.

Answers:

(1-5): 
In each step numbers and words are arranged at the left and then shift rightward such that for the numbers, are arranged in ascending order from right to left, while for words, the number of letters present in the word are arranged in ascending order from right to left in the final arrangement.
Input: forsake 36 ebullience page 89 10 quack 42 amicable 56 21 redact
Step I: page 10 forsake 36 ebullience 89 quack 42 amicable 56 21 redact
Step II: quack 56 page 10 forsake 36 ebullience 89 42 amicable 21 redact
Step III: redact 21 quack 56 page 10 forsake 36 ebullience 89 42 amicable
Step IV: forsake 42 redact 21 quack 56 page 10 36 ebullience 89 amicable
Step V: amicable 89 forsake 42 redact 21 quack 56 page 10 36 ebullience
Step VI: ebullience 36 amicable 89 forsake 42 redact 21 quack 56 page 10

1. 2     
2. 4            
3. 3             
4. 3                 
5. 4

6. 5; Some colleges are hostels (I) + No hostel is an institute (E) = I + E = O = Some colleges are not institutes. However, the possibility mentioned in conclusion I exists. Hence, I follows.
Again, No hostel is an institute → conversion → No institute is a hostel. Hence, conclusion II follows.

7. 2; All hammers are needles (A) + Some needles are threads (I) = A + I = No conclusion. Hence, conclusion I does not follow. There is no negative statement. Thus, possibility in II exists. Hence, conclusion II is inherent in first statement.

8. 5; All shells are boxes (A) + All boxes are pearls (A) = A + A = A = All shells are pearls. Hence, conclusion I follows.
Again, Some stones are shells (I) + All shells are boxes (A) = I + A = I = Some stones are boxes. Hence, conclusion II follows.

9. 4; All chains are bangles (A) + Some bangles are pendants (I) = A + I = No conclusion. Hence, conclusion I does not follow.
Again, All chains are bangles → conversion → Some bangles are chains. Hence, conclusion II does not follow.

10. 2; No pendant is a ring →  conversion → No ring is a pendant. Hence, conclusion I does not follow.
Again, All chains are bangles → conversion → Some bangles are chains. Hence, conclusion II follows.

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